Using Template Variable in the content area of a document to past it a snippet

Hi everyone,

I wonder if it is possible to take the current document id like that [~id~] inside the content area of a document
so that i can past it directly to the snippet in the same area exemple : [[MySuperSnippet? &docid=[~id~]]].

The goal of doing this is that i want to use that technique so that don’t need to copy and paste it in each content
area of each document that i will create in the future. I want to put that in a template so that it’s run by that template
and it apply the snippet to every document with that template

Using this [[listerDepartsVoyage? &idVoyage=`[*id*]`]]

i’am able to pass the id of the current document and the snippet receive the value without a problem
because i test with an echo but when i’am trying to get the child documents like that :

$enfants = $modx->getDocumentChildren($idVoyage, 0, 0, ’id’);

it doesn’t work but when i replace [[listerDepartsVoyage? &idVoyage=`[*id*]`]] by [[listerDepartsVoyage? &idVoyage=22]]

it does work that is kind of bizzare. I don’t understand why can you help me please ?

**** Note : the child document of id = 22 are not published so i’am presuming that the second parameter if getDocumentChildren is fine !

Not sure it’s the solution but you can try an uncached call: [!listerDepartsVoyage? &idVoyage=`[*id*]`!]

That is working but i don’t understand why is that working!
what if the difference between double brace and single brace ?

great useful help for my first post thank you so much !
i will ask you more stuff coming so be ready my brethren.

It has to do with the parser. For some things it needs to do a first pass to get initial data and if cached it will not do this pass. This is a simplified answer but is a deep as I understand

Quote from: dev_cw at Feb 13, 2008, 02:09 PM

It has to do with the parser. For some things it needs to do a first pass to get initial data and if cached it will not do this pass. This is a simplified answer but is a deep as I understand

i understand now as deeply as you !
thank you !

When the parser goes through a document it runs all the [[SnippetName]] code through the eval() function to run the PHP in the snippet as it comes to them. So if both snippets are [[SnippetName]] style, the value of the inner snippet is evaluated AFTER the outer snippet, but the outer snippet needs the returned value of the inner snippet to run!

If you have [!OuterSnippet? &myParam=`[[InnerSnippet]]`!] the [!OuterSnippet is skipped, the [[InnerSnippet]] gets evaluated and its tags are replaced by its returned value. Then at the end, the parser sees that there is now [!OuterSnippet? &myParam=`value`!], converts the [! and !] tags to [[ and ]], and runs the document through again, this time evaluating [[OuterSnippet? &myParam=`value`]] and it works.

Quote from: sottwell at Feb 13, 2008, 10:52 PM

When the parser goes through a document it runs all the [[SnippetName]] code through the eval() function to run the PHP in the snippet as it comes to them. So if both snippets are [[SnippetName]] style, the value of the inner snippet is evaluated AFTER the outer snippet, but the outer snippet needs the returned value of the inner snippet to run!

If you have [!OuterSnippet? &myParam=`[[InnerSnippet]]`!] the [!OuterSnippet is skipped, the [[InnerSnippet]] gets evaluated and its tags are replaced by its returned value. Then at the end, the parser sees that there is now [!OuterSnippet? &myParam=`value`!], converts the [! and !] tags to [[ and ]], and runs the document through again, this time evaluating [[OuterSnippet? &myParam=`value`]] and it works.

Men that’s deep enough for the RECURSIVITY lol thanks a lot !