Pass custom PHP output to a TV

284 Posts

legues Reply #1, 12 years, 8 months ago

Hi Guys

I´ve got a question... i have a situation where i have custom php code inside of a snippet. How can i pass the output of this custom php code to a TV? The TV value should always be the output of my custom php code even when the output it´s updated!!!
Is this possible?

My php code:

<?php
$description = mysql_query
("
	SELECT  `rates_packages`.`description`
	FROM  `rates_packages` 
	WHERE  `rates_packages`.`id` = 1
	AND  `rates_packages`.`published` =1
	AND  `rates_packages`.`deleted` !=1
");

$d = mysql_fetch_array($description);

echo $d['description'];

Many thanks in advance

5,888 Posts

Bruno17 Reply #2, 12 years, 8 months ago

I don't understand, what's the reason to have a TV, which does allways show the same content.
Can't you just put the snippet-tag into the template?

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Thanks!

284 Posts

legues Reply #3, 12 years, 8 months ago

Quote from: Bruno17 at Jan 13, 2014, 07:58 AM

I don't understand, what's the reason to have a TV, which does allways show the same content.
Can't you just put the snippet-tag into the template?

Because i need a TV value to push the php code output with the getresources. I tried to put the snippet inside my TV, it show on the page, but it´s not pushed by getresources!!!!

284 Posts

legues Reply #4, 12 years, 8 months ago

Quote from: Bruno17 at Jan 13, 2014, 07:58 AM

I don't understand, what's the reason to have a TV, which does allways show the same content.
Can't you just put the snippet-tag into the template?

The reason is that i have more that one snippet that i want to use in the TV, according the Resource. But then when i want to retrieve the value with getresources or Advsearch from my TV, it won´t show me any data, but in the resource it does... why?

Check the attached picture, please!!!!

Many thanks to try to help me!!!