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Answered Looking for a very simple slideshow solution.

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    • 15 Posts
    kahli Reply #11, 11 years, 5 months ago
    Whistlemaker, I wound up using your php to create an unordered list of all the jpeg files in the directory, and then using a javascript slideshow tutorial I found.

    I have one question - is it possible, using your php, to include the file name of each image without the .jpg extension, in a paragraph tag? What would I have to add to the following to add that where I have "File Name Here"?

    $files = scandir($imagedir);
  
$html = '<ul class="slides">';
 
foreach ($files as $filename) {
    if(strstr($filename, '.jpg'))
    {
        $html .= '<li><img src="'.$imagedir.'/'.$filename.'" alt=" " /><p class=flexcaption>"File Name Here"</p></li>';
    }
} 
  
$html .= '</ul>';
  
return $html;


    Unfortunately I have no knowledge of PHP (it's on my list of things to learn, but unfortunately time hasn't permitted at this stage).

    Thank you so much everyone for your help.
    • discuss.answer
      sottwell Reply #12, 11 years, 5 months ago
      You'll want the "basename()" function: http://php.net/manual/en/function.basename.php
      <p class=flexcaption>'. basename($filename, '.jpg') .'</p>

      [ed. note: sottwell last edited this post 11 years, 5 months ago.]
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        • 39073
        • 15 Posts
        kahli Reply #13, 11 years, 5 months ago
        Thank you Susan!!!

        Can't believe it was so easy - I was looking on stack overflow and all the answers involved multiple lines of code, "if"s and "for"s.

        Thanks.
        • sottwell Reply #14, 11 years, 5 months ago
          For interesting additional information and usage, see the comments to the PHP documentation, especially Swedish Boy's example of using basename() to strip a variable extension using the pathinfo() function to determine the actual extension, then using basename() to get the stripped filename.
          $file = 'image.jpg';

$info = pathinfo($file);
$file_name =  basename($file,'.'.$info['extension']);

echo $file_name; // outputs 'image'
            Studying MODX in the desert - http://sottwell.com
            Tips and Tricks from the MODX Forums and Slack Channels - http://modxcookbook.com
            Join the Slack Community - http://modx.org
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            whistlemaker Reply #15, 11 years, 5 months ago
            glad my code helped

            the php docs and the comments to them are very helpful both as a reference and a learning tool - I use them before doing any internet search, usually with good results.