yyyy-mm-dd to Age (almost working)

  

echo $dob; // this was passed in via snippet call parameter and Outputs "1962-04-23" correctly.
echo gettype($dob); // it is in fact a string ;)

$dob2="1962-04-23";
echo gettype($dob2); // it is in fact a string as well ;)

//So in theory $dob and $dob2 are the exact same thing with the exact same value, however when I //use $dob below (snippet param), it outputs 2013 (wrong) but when I use $dob2 (hard coded above) it outputs //"50" like it is supposed to.

$y = explode("-", $dob);		
			$year = date("Y") - $y[0];
			if (date("m") >= $y[1])
				if (date("d") >= $y[2])
					$year++;
return $year;  

[[formatAge? &dob=`[[+dob:date=`%Y-%m-%d`]]`]]

  

$age = intval(substr(date('Ymd') - date('Ymd', $dob), 0, -4));

$age = intval(substr(date('Ymd') - date('Ymd', strtotime($dob)), 0, -4));

if (is_string($dob)) {
    $age = intval(substr(date('Ymd') - date('Ymd', strtotime($dob)), 0, -4));
} else {
    $age = intval(substr(date('Ymd') - date('Ymd', $dob), 0, -4));
}

 

echo "dob = $dob"; // returns 1983-10-20 or 435456000 depending on my resource call 
if (is_string($dob)) {
    $age = intval(substr(date('Ymd') - date('Ymd', strtotime($dob)), 0, -4));
} else {
    $age = intval(substr(date('Ymd') - date('Ymd', $dob), 0, -4));
}
echo "   now the dob = ";
return $age;  // returns 42, if i change the date, the answer is still 42.

[[!SnippetName]]