Replacing a TV value with it's name

93 Posts

feary Reply #1, 19 years, 9 months ago

I didn’t expect this to be that hard, but... it was

I have a TV called "fylke" which contains the input options:

Ostfold==1||Aust-Agder==2||Buskerud==3||Finnmark==4||Hedmark==5||Hordaland==6||More og Romsdal==7||Nord-Trondelag==8||Nordland==9||Oppland==10||Oslo og Akerhus==11||Rogaland==12||Sor-Trondelag==13||Sogn og Fjordane==14||Svalbard==15||Telemark==16||Troms==17||Vest-Agder==18||Vestfold==19

I have about 30 documents each containing the TV value (by their value, of course). Now I want to output the TV by it’s name and not their value, in the documents but also in the Ditto call listing them. Anyone?

3,250 Posts

MARKSVIRTUALDESK Reply #2, 19 years, 9 months ago

Here is a snippet that would do that:

This assumes that the tv parameter is passed to it with the numeric value of the tv


$tvData = explode("||",$tv)
foreach ($tvData as $item) {
$tvItem = explode("==",$item);
if ($tvItem[1] == $tv) {
return $tvItem[0];
}
}

Note: code is not tested

93 Posts

feary Reply #3, 19 years, 9 months ago

Thanks, Mark. Could you please specify how I pass the Ditto tv parameter to the snippet?

3,250 Posts

MARKSVIRTUALDESK Reply #4, 19 years, 9 months ago

[[snippetName?tv=`[+tvNameOfTV+]`]]

Note the tv prefix.

93 Posts

feary Reply #5, 19 years, 9 months ago

My snippet (getFylkeName) looks like this:

$tv = isset( $tv ) ? $tv : "";
$tvData = explode("||",$tv);

foreach ($tvData as $item) {
$tvItem = explode("==",$item);
if ($tvItem[1] == $tv) {
return $tvItem[0];
}
}

And I’m using this call [[getFylkeName?tv=`[+tvfylke+]`]]
The TV is passed to the snippet correctly, but it outputs nothing when the snippet is parsed. sad