Calling a snippet from within a snippet

From the documentation -

Snippets can also be run inside of other snippets by using the MODx API:
Usage:
$modx->runSnippet(’snippetName’);

If I do it exactly like that it works, however I need to pass a parameter in so I put

$modx->runSnippet(’snippetName?&id=53’); (I also tried it with quotes around the "53")

This breaks it, and the snippet is not called.

Is it possible to pass a parameter and, if so, what is the correct way to do it?

Thanks.

That’s coming in a future (not 0.9.1) recursive parser that’s being tested in parallel with our next/imminent release.

I can’t wait

To understand recursion one must first understand recursion

Actually, you can call a snippet from within another snippet using the API. You pass the parameters as an array, in the second argument to the runSnippet() function...



What Ryan is talking about in regards to the recursive parser is being able to do this in the content...

Quote from: OpenGeek at Dec 22, 2005, 04:02 PM

Actually, you can call a snippet from within another snippet using the API. You pass the parameters as an array, in the second argument to the runSnippet() function...

$snippetName= 'MySnippetName';
$snippetParams= array('id'=> 53);
$modx->runSnippet($snippetName, $snippetParams);

That’s a new discovery from me.
I thought we have to set the variables before that, and force the snippet that was called from other snippet to use global variables.

Anyway, thanks for the great info.

Thanks Jason,

that’s what I was hoping to hear. I have been using a session variable temporarily.

Forgive my ignorance but how do I retrieve the parameters at the called end?

The parameters basically get extracted into the scope of the eval, so add a $ in front of the parameter name, and there you have it...

for instance, the `id` parameter of a snippet would be available as $id

The documentation needs to be updated with the ability to pass parameters to it.