[ Ditto ] - how to display all children documents content

Hi everyone
I’m new to Modx and got question.
How to display all child documents content as they are without any &tpl to format them.
Eg: I have one main document and every child document has it’s own content (some text or other diffrent Ditto executions). I want to display all children regarding content only with no template.
Is it possible with Ditto? If so, how can I make it work? If not, what should I do?

p.s. I need to generate XML from child documents dynamicly thats why I need it that way.

I’ll be very happy for any help! Thanks.

whell you always need an &tpl to show somthing but the contents of that tpl could just be [+content+] that way ditto will show the content you could do somthing like this:

[!ditto? &parents=`12` &tpl=`@CODE [+content+]` total =`all` !]

the problem with ditto on the pages you grab with ditto is that they need to be cahed or it will not parse. and the main call should be uncached like above call.


Dimmy

thanks mate, but it doesn’t work as expected.

the result is:

<p>&tpl either does not contain any placeholders or is an invalid chunk name, code block, or filename. Please check it.</p><p>&tpl either does not contain any placeholders or is an invalid chunk name, code block, or filename. Please check it.</p><p>&tpl either does not contain any placeholders or is an invalid chunk name, code block, or filename. Please check it.</p>` ]]` ]]` ]]` ]]` ]]` ]]` ]]` ]]` ]]` ]]` ]]` ]]` ]]` ]]` ]]` ]]` ]]` ]]` ]]` ]]` ]]` ]]` ]]` ]]` ]]` ]]` ]]` ]]` ]]` ]]` ]]` ]]` ]]` ]]` ]]` ]]` ]]` ]]` ]]` ]]` ]]` ]]` ]]` ]]` ]]` ]]` ]]` ]]` ]]

here’s site structure:

I want to display only [content] field (text only) of Head, Content and Footer section.
Eg. Head section contains code:


and what if child document content has another Ditto execution for displaying it’s children?
maybe there is another way, without Ditto to pull child content on it’s parent?

i want only text data from children, because MODx will pull out XML data for FLASH site.

I have a similar prob, if anyone could suggest a way

Try like this:

add this call in your template and change the id for &parents=``:


then create "dittotemplate" chunk, with this:

Another way to count Ditto docs:



Not sure why paginate is required though hey it didn’t return a value without.

Chunk doc-count uses Ditto placeholder [+total+]

Because the page count is part of the pagination function, and isn’t implemented unless the pagination is specified.

Thanks Susan