Support/Comments for EasyCopyright 1.1-pl

- 7 Posts
redesb Reply #11, 14 years, 2 months ago
Thank you for your answers 'Frogabog' and 'AMDbuilder'.

But I solved it by setting a small 'snippet', was not so hard, I describe below in case anyone wants to use it.

The call:
```
[[CopyrightYears? &iniYear=`2011`]]
```
The 'snippet' Code:
```
$year = date('Y');
$output = '&copy; ' . $iniYear;
if($year > $iniYear){$output .= '-' . $year;}
$output .= ' &middot; <span><a href="' . $modx->getOption('site_url') .'">' . $modx->getOption('site_name') . '</a></span>';
return $output;
```
NOTE: I used the <span> tags to change the font type, but not necessary.

What you get:

© 2011-2012 · TheSiteName

When set iniYear to 2012, yo get:

© 2012 · TheSiteName

Hope this helps someone,
Ramon [ed. note: redesb last edited this post 14 years, 2 months ago.]