Problem passing [*content*] placeholder to a snippet on template

Hey all

i have a snippet call like this:

[!mysnippet?&content=`[*content*]` !]

What happen is that, if i send some html like this:

[!mysnippet?&content=`<p color='red'>Yeah</p>` !]

it will return this:

<p colo

the [test only] snippet code (mysnippet) is:

<?php
return $content;
?>

Why is this happening? My actual snippet is converting html to pdf, so i really need this.

Thank you all

EDIT: I’m using Modx Evo 1.0.2

You could use &docid=`[*id*]` in your snippet call

Then in your snippet:

<?php
$output = $modx->db->getValue('SELECT `content` FROM `modx_site_content` WHERE `id` = '.$docid.'');
return $output;
?>

But if the snippet is just going to read current document use no params at all in snippet call!

<?php
$var1 = $modx->documentObject['content'];
$var2 = $modx->documentObject['pagetitle'];

$output = <<<END 
<h1>$var1</h1>
<p>$var2</p>
END;
return $output;
?>

http://svn.modxcms.com/docs/display/Evo1/Document+Object

Interesting: http://stackoverflow.com/questions/tagged/modx

[!topdf? &content=`[*content*]`!]

You can’t use "=" in a snippet tag except to assign parameters. The secret is to change it to something else (e.g. "EQUALS"), then use str_replace() in the snippet to change it back.

Parsed content? Try http://modxcms.com/forums/index.php/topic,46561.msg274314.html#msg274314

$output = $modx->parseDocumentSource($content);

$content = $modx->parseDocumentSource($modx->documentObject['content']);
echo $content;

...
<h3>Pacotes no Orçamento:</h3>
<p>
[!Ditto? &id=`orcamento` &parents=`73` &level=`1` &tpl=`md.orcamento.formvars` &noResults=` ` &orderBy=`menuindex ASC` !]
</p>
<p color="red">Yeah TEST</p>
...

why not call your snippet like this:

[!topdf!]

and in your snippet:

$content=$modx->documentObject['content'];