Insert content from a content page into my template file

85 Posts

need4speed Reply #1, 15 years, 11 months ago

I want to take the content from a content page and insert it into another page in my template.

How can I do that?

85 Posts

need4speed Reply #2, 15 years, 11 months ago

No suggestion? I just want to take the content from one content page and insert it,into my template file.

194 Posts

Pandy06269 Reply #3, 15 years, 11 months ago

Your question is not overly clear. I’m taking this as, for example, your template is rendering the content for page 1, but you want to insert the content from page 2 somewhere in the HTML?

What I would do is create a snippet that takes a resource ID as a parameter, looks up the resource from the database, and returns the content.

You will then be able to put

[[YourSnippetName? &docId=`2`]]

in your template.

Use the following code as guidance - it’s possibly not 100% correct and there’s no error or sanity checking so isn’t production-ready:

$c = $modx->newQuery('modResource');  
$c->where(array(
  'published' => true,  
  'deleted' => false,
  'id' => $docId
));
$resources = $modx->getCollection('modResource', $c);

return $resources[0]->get('content');

Alternatively you might be able to use the getResources snippet from the modx Extras directory.

85 Posts

need4speed Reply #4, 15 years, 11 months ago

I got this error:

Fatal error: Call to a member function get() on a non-object in /var/www/xxxx.dk/public_html/core/cache/elements/modsnippet/44.include.cache.php on line 15

I create the snipped called addcontent with the php code and added this snippet to my template: [[addcontent? &docId=`24`]]

Can you make it work laugh

?

24,544 Posts

BobRay Reply #5, 15 years, 11 months ago

Possibly your document is not published?

At any rate, you could simplify the code to this, which would be faster:

<?php
$resource = $modx->getObject('modResource', $docId);

if ($resource) {
    return $resource->getContent());
} else {
    return 'Resource Not Found';
}

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194 Posts

Pandy06269 Reply #6, 15 years, 11 months ago

Quote from: BobRay at Oct 28, 2010, 03:29 PM

At any rate, you could simplify the code to this, which would be faster:
<?php
$resource = $modx->getObject('modResource', $docId);

if ($resource) {
    return $resource->getContent());
} else {
    return 'Resource Not Found';
}

Nice tip, BobRay, thanks.

5,888 Posts

Bruno17 Reply #7, 15 years, 11 months ago

or just with getResourceField:

[[getResourceField? &id=`[[*parent]]` &field=`content` ]]

-------------------------------

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Thanks!

85 Posts

need4speed Reply #8, 15 years, 10 months ago

I think Im stupid or something.

I have created the snippet:

<?
$resource = $modx->getObject(’modResource’, $docId);

if ($resource) {
return $resource->getContent());
} else {
return ’Resource Not Found’;
}

And in my template i have added the line: [[AddContent? &docId=`34`]]

And it says: /public_html/core/cache/elements/modsnippet/44.include.cache.php on line 10

85 Posts

need4speed Reply #9, 15 years, 10 months ago

Okay I got it to work after I installed the getResourcefield

And used this line: [[getResourceField? &id=`53` &field=`content` ]]

Thank you all for your help!