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MODX Community Forums Archive

how to find if resource has children?

    • 3749
    • 24,544 Posts
    BobRay Reply #11, 15 years, 4 months ago
    The code above seems like overkill to me (and it makes me nervous to use PHP reserved words as variable names):

    [[!HasChildren? &id = `23`]]



    <?php
$document = $modx->getObject('modResource', $id);

if($document){
    return $document->hasChildren()? 'hasChildren' : 'noChildren';
}

return '';


    or, if you want to use isfolder instead:

    <?php
$document = $modx->getObject('modResource', $id);

if($document){
    return $document->get('isfolder')? 'hasChildren' : 'noChildren';
}

return '';
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      • 1,624 Posts
      cipa Reply #12, 15 years, 4 months ago
      I agree. Simple is better smiley

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        • 44 Posts
        krisj Reply #13, 15 years, 4 months ago
        thats elegant BobRay wink thanks!
          • 16337
          • 44 Posts
          krisj Reply #14, 15 years, 4 months ago
          Quote from: BobRay at May 11, 2011, 11:42 PM

          The code above seems like overkill to me (and it makes me nervous to use PHP reserved words as variable names):

          [[!HasChildren? &id = `23`]]



          <?php
$document = $modx->getObject('modresource', $id);

if($document){
    return $document->hasChildren()? 'hasChildren' : 'noChildren';
}

return '';


          or, if you want to use isfolder instead:

          <?php
$document = $modx->getObject('modresource', $id);

if($document){
    return $document->get('isfolder')? 'hasChildren' : 'noChildren';
}

return '';


          warning - if someone uses this, yous should have "modResource" instead of "modresource" within the code samples above.

          other than that it works a treat.

          thanks guys.
            • 3749
            • 24,544 Posts
            BobRay Reply #15, 15 years, 4 months ago
            Good catch (fixed above). Sorry for any confusion. tongue
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              • 51315
              • 67 Posts
              fredela Reply #16, 8 years, 10 months ago
              Quote from: BobRay at May 11, 2011, 06:42 PM
              The code above seems like overkill to me (and it makes me nervous to use PHP reserved words as variable names):

              [[!HasChildren? &id = `23`]]



              <!--?php
$document = $modx--->getObject('modResource', $id);

if($document){
    return $document->hasChildren()? 'hasChildren' : 'noChildren';
}

return '';


              or, if you want to use isfolder instead:

              <!--?php
$document = $modx--->getObject('modResource', $id);

if($document){
    return $document->get('isfolder')? 'hasChildren' : 'noChildren';
}

return '';

              Dear Bob,
              I know it's an old post, but what if we want to find out if a parent's resource has children, but also if that same resource has a published status?
              Example: I need to generate the class "hasChildren" only if a parent has a child who is also published.
                • 4172
                • 5,888 Posts
                Bruno17 Reply #17, 8 years, 10 months ago
                you can try this:

                       $document = $modx->getObject('modResource', $id);
        
       if($document){
           $c = $modx->newQuery('modResource');
           $c->where(array(
               'parent' => $document->get('id'),
               'published' => '1',
               'deleted' => '0'
           ));
           $has_children = $modx->getCount('modResource',$c);           
           return $has_children ? 'hasChildren' : 'noChildren';
       }
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                  • 51315
                  • 67 Posts
                  fredela Reply #18, 8 years, 10 months ago
                  Thank you Bruno, works like a charm!
                    • 51315
                    • 67 Posts
                    fredela Reply #19, 8 years, 10 months ago
                    Quote from: Bruno17 at Nov 07, 2017, 02:40 PM
                    you can try this:

                           $document = $modx->getObject('modResource', $id);
        
       if($document){
           $c = $modx->newQuery('modResource');
           $c->where(array(
               'parent' => $document->get('id'),
               'published' => '1',
               'deleted' => '0'
           ));
           $has_children = $modx->getCount('modResource',$c);           
           return $has_children ? 'hasChildren' : 'noChildren';
       }

                    Actually, this snippet suggests many situations.
                    For instance, it works perfectly with pdoMenu to hide a parent resource if no published children are found.

                    hasChildren = show = display: none
                    noChildren = hide = display: block
                    &tpl=`@INLINE <span class="[[!hasChildren?&id=`[[+id]]`]]"><a href="[[+link]]">[[+menutitle:]]</a>[[+wrapper]]</span>`