Help! How do I call a snippet from a snippet?

7 Posts

jtp313 Reply #1, 16 years, 1 month ago

I’m using the new MODx Revolution 2.0.2-pl
I’m just trying to call a snippet from within a snippet. They look like below
I get this:
Parse error: syntax error, unexpected ’[’ in C:\xampp\htdocs\cmapp\core\cache\elements\modsnippet\2.include.cache.php on line 7

Snippet1:
[[Snippet2]]

Snippet2:
if ($modx->user->isMember(’SuperUser’)) {
return ’3’;
}

659 Posts

anso Reply #2, 16 years, 1 month ago

Try

Snippet1

$snippetName = 'mySnippet';
$modx->runSnippet($snippetName);

// OR if you have parameters in your snippets you can pass them as an array and do
$modx->runSnippet($snippetName,$parameters);

Cheeers

7 Posts

jtp313 Reply #3, 16 years, 1 month ago

Snippet1 displays nothing. Snippet2 displays "3".
As below.

Snippet1:
$runcheck = "Snippet2";
$modx->runSnippet($runcheck);

Snippet2:
<?php
if ($modx->user->isMember(’SuperUser’)) {
return ’3’;
}

7 Posts

jtp313 Reply #4, 16 years, 1 month ago

Does anyone know how to do this or how to make something like this work?
I don’t want to have to write a bunch of checks into each snippet, I’d rather call another snippet. I’d like to assign a variable in my script based on a snippet return.

5,888 Posts

Bruno17 Reply #5, 16 years, 1 month ago

Snippet1:

<?php
$runcheck = 'Snippet2';
return $modx->runSnippet($runcheck);

or:

<?php
$runcheck = 'Snippet2';
$output = $modx->runSnippet($runcheck);
return $output;

Snippet2:

<?php
if ($modx->user->isMember('SuperUser')) {
  return '3';
}

-------------------------------

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Thanks!

7 Posts

jtp313 Reply #6, 16 years, 1 month ago

I really hate it when the answer is that easy. I should have noticed the missing return.
Thanks for your help!