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☆ A M B ☆
- 279 Posts
Hi all,
When you have a lexicon with an placeholder inside, you can replace it simple by calling [[%lexicon.key? &placeholder=`content`]]
But how could I do this inside Extjs for the manager? I now dit .split(’[[+placeholder]]’).join(’content’) but I can imagine there is a better way to do this.. Let me know!
Regards Bert
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☆ A M B ☆
- 279 Posts
Something like _(’name’, { placeholder: content }); would be great! But I can’t find it in the documentation