[Resolved] Codding in a snippet

Hi all,
I’ve a problem, there it is :
I create a nippet with this code :



Then, i load my snippet :


Simple ^^ However, my snippet return empty, the global in my function doesn’t work ?
Has someone any idea ? (sorry for my english ;p)

Try this.



You could certainly build it around a function but you always need to return a value string, or array as the output of the snippet not an echo statement.

Not to mention your snippet call should be as follows [!mysnippet!] or [[mysnippet]] not [!mysnippet]]

Hi

there a couple of errors in your sample coade and snippet call

<?php

$uid = 2 // ; is missing
function get_profil() {

and snippet call are [[... means cached call...]] and [!... means uncached...!]
you ’re mixing the syntax starting with a [! and closing by ]] so it cannot work.

:-)

ok, i tried like this :



Then, i load my snippet :


My snippet is still return me nothing :/
ps smashingred : You remove my function, this code is an exemple. I need my function :/

My Modx Version is 0.9.6.2

You need to declare $uid as a global outside the function

global $uid;
$uid = 2;

function() {
global $uid;


} ....


:-)

Ok it works, great.
Really thanks, i close my post

Ps : heliotrope : Calling a snippet with [!...]] works, i don’t know if it’s recommended, but it works like [!....!].

[! means it’s uncached and evaluated every time the page is visited. It’s not only recommended, but required in this case.