Hide part of the template by query string parameter

1 Posts

alex747 Reply #1, 9 years, 6 months ago

Hi,

I need to hide part of the template when the query string (GET) variable is present. I've tried <?php if (isset($_GET['ok'])) { ?> OK <?php } ?>, tried google for "hide by get parameter modx", etc but nothing found. How to do that?

Kind Regards,
Alex

1,145 Posts

donshakespeare Reply #2, 9 years, 6 months ago

https://modx.com/extras/package/geturlparam

//www.example.com?myString=awesome

[[!getUrlParam:is=`awesome`:then=`
<link rel="stylesheet" type="text/css" media="screen" href="[[++assets_url]]myString.css">
<link rel="stylesheet" type="text/css" media="screen" href="[[++assets_url]]myString123.css">
`?
&name=`myString`
]]

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Bruno17 Reply #3, 9 years, 6 months ago

or fastfield-tags (included with pdoTools)

load the chunk 'yourChunk' if the url-param ok = 1:

[[[[!#get.ok:is=`1`:then=`$yourChunk`]]]]

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194 Posts

DonQuicky Reply #4, 9 years, 6 months ago

Quote from: Bruno17 at Mar 07, 2017, 01:37 AM

or fastfield-tags (included with pdoTools)

load the chunk 'yourChunk' if the url-param ok = 1:
[[[[!#get.ok:is=`1`:then=`$yourChunk`]]]]

Thanks Bruno,

I am a fan of pdoTools and this one is new to me

Still learning!

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