Latest Images without a gallery

Hello,

I’m having a good time with ModX at the moment, it’s proving very easy to get to grips with.

I was wondering if it’s possible to show the latest image from a directory, without the aid of a photo gallery?

Any help would be appreciated.

Thanks,

You could use a snippet or a TV, with @EVAL, and write the code to get the latest image from a given directory.

http://il2.php.net/manual/en/ref.dir.php

Ah. Thanks for the help, it’s a little above my station though. I really need to learn this php malarky if I’m to get anywhere in this world, heh.

I take it there’s no shortcuts with this one then?

Thanks GaneshXL,

I did try googling but couldn’t find anything. I’ll give it a shot, cheers!

I’m having this problem seemingly:

I’m using it in a snippet, though I’m not sure how to use the ’return()’ statement.

PHP error debug
Error: opendir([(base_url)]/assets/files/downloads/icons/) [function.opendir]: failed to open dir: No error

Error type/ Nr.: Warning - 2
File: C:\xampp\htdocs\modx\manager\includes\document.parser.class.inc.php(766) : eval()’d code Line: 8

Any help would be great

Check the permissions on that directory. Make sure it’s set to at least 755, or maybe 777.

Quote from: sottwell at Nov 15, 2007, 12:36 PM

Check the permissions on that directory. Make sure it’s set to at least 755, or maybe 777.

I’m running locally with XAMP on Windows, how do I go about changing permissions? I would be fine if it was remote

Quote from: ganeshXL at Nov 15, 2007, 04:25 PM

PHP doesn’t parse [(base_url)] when used in a snippet - take a close look at your error msg:
Error: opendir([(base_url)]/assets/files/downloads/icons/) [function.opendir]: failed to open dir:

In a snippet, use something like:
$dir = $modx->config[’base_path’] . ’/assets/files/downloads/icons/’;

Ah thanks, I haven’t worked with snippets until now, so I thought it was all the same. However I’m now getting this error:

Parse error: syntax error, unexpected T_STRING in C:\xampp\htdocs\modx\manager\includes\document.parser.class.inc.php(766) : eval()’d code on line 4

Bescause I know nothing about PHP I feel I stand very little chance of debugging this without help. I’m looking into learning at least the basics.

Okay sorry, I’m being a php tard. I’ve figured it out now.

My problem is that with this script it shows a link to the image, rather than the image itself. I’ll keep fiddling and try to change it, but any ideas in the mean time would be great.

Once i’ve figured this out I guess I can apply it to any free snippets of php I come across?

Okay cool, I’ve got it to work!

I’m now trying to exclude any files starting with a ’.thumb’. I have the following bit of code I’ve scabbed from another post, but don’t know how to apply it to this situation:



A quick pointer would be appreciated